5(x^2)-2x-39=0

Solution for 5(x^2)-2x-39=0 equation:

5(x^2)-2x-39=0

a = 5; b = -2; c = -39;
Δ = b2-4ac
Δ = -22-4·5·(-39)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-28}{2*5}=\frac{-26}{10}
=-2+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+28}{2*5}=\frac{30}{10}
=3
$